6x+2[5(x+1)+8]=38

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Solution for 6x+2[5(x+1)+8]=38 equation:


Simplifying
6x + 2[5(x + 1) + 8] = 38

Reorder the terms:
6x + 2[5(1 + x) + 8] = 38
6x + 2[(1 * 5 + x * 5) + 8] = 38
6x + 2[(5 + 5x) + 8] = 38

Reorder the terms:
6x + 2[5 + 8 + 5x] = 38

Combine like terms: 5 + 8 = 13
6x + 2[13 + 5x] = 38
6x + [13 * 2 + 5x * 2] = 38
6x + [26 + 10x] = 38

Reorder the terms:
26 + 6x + 10x = 38

Combine like terms: 6x + 10x = 16x
26 + 16x = 38

Solving
26 + 16x = 38

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-26' to each side of the equation.
26 + -26 + 16x = 38 + -26

Combine like terms: 26 + -26 = 0
0 + 16x = 38 + -26
16x = 38 + -26

Combine like terms: 38 + -26 = 12
16x = 12

Divide each side by '16'.
x = 0.75

Simplifying
x = 0.75

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